Series, Convergence Tests and Taylor Polynomials
AP Calculus BC, Unit 10. Which convergence test to use and when, interval of convergence with endpoint checks, the standard Maclaurin series, Taylor polynomials and the two error bounds.
Unit 10, Infinite Sequences and Series, exists only in AP Calculus BC, and it carries a free response question almost every year. The unit rewards a clear decision process more than clever tricks.
Choosing a convergence test
| Series looks like | Try first | ||
|---|---|---|---|
| Terms do not tend to 0 | nth term test: it diverges | ||
Σ arⁿ | Geometric: converges when ` | r | < 1, to a/(1 − r)` |
Σ 1/nᵖ | p-series: converges when p > 1 | ||
| Alternating signs | Alternating series test | ||
| Factorials or powers of n | Ratio test | ||
| Similar to a known series | Comparison or limit comparison | ||
| A function you can integrate | Integral test |
Two warnings graders check every year:
- If
lim aₙ = 0, the nth term test says nothing.Σ 1/nhas terms tending to 0 and still diverges. - A ratio test limit of exactly 1 is inconclusive. Switch tests.
Absolute and conditional convergence
A series converges absolutely if Σ |aₙ| converges. It converges conditionally if it converges but Σ |aₙ| does not. Σ (−1)ⁿ⁺¹/n is the standard example of conditional convergence.
Interval of convergence
- Apply the ratio test to the power series and solve the inequality for
x. - The ratio test says nothing at the endpoints, so test each endpoint separately.
Worked example: Σ (x − 2)ⁿ / (n · 3ⁿ) for n ≥ 1.
- Ratio:
|x − 2|/3 × n/(n + 1)tends to|x − 2|/3, so the series converges when|x − 2| < 3, that is−1 < x < 5. - At
x = 5the series isΣ 1/n, which diverges. - At
x = −1it isΣ (−1)ⁿ/n, which converges by the alternating series test. - Interval of convergence:
[−1, 5). Radius: 3.
Taylor and Maclaurin series
f(x) = Σ f⁽ⁿ⁾(a)/n! × (x − a)ⁿ
A Maclaurin series is the case a = 0. Know these four without deriving them:
eˣ = 1 + x + x²/2! + x³/3! + ...for allxsin x = x − x³/3! + x⁵/5! − ...for allxcos x = 1 − x²/2! + x⁴/4! − ...for allx1/(1 − x) = 1 + x + x² + x³ + ...for|x| < 1
New series come from these by substitution, differentiation and integration. For example, replacing x with −x² in the last line gives 1/(1 + x²), and integrating that gives the series for arctan x.
The two error bounds
- Alternating series error bound: when the series alternates and its terms decrease to 0, the error after stopping is at most the first omitted term.
- Lagrange error bound: for a Taylor polynomial of degree
nabouta,
> |Rₙ(x)| ≤ M |x − a|ⁿ⁺¹ / (n + 1)!
where M bounds |f⁽ⁿ⁺¹⁾| between a and x.
The free response approach
Name the test you use and show that its conditions hold. For an interval of convergence, write the endpoint checks explicitly. For an error bound, say which bound you use and why it applies.
Short Lesson Video
Mock Exam
Practice Quiz
Test yourself: instant results and explanations.
1. What is the interval of convergence of Σ (n = 1 to ∞) xⁿ/n?
2. For a series Σ aₙ, the terms satisfy lim aₙ = 0. What does the nth term test conclude?
3. What are the first three nonzero terms of the Maclaurin series for sin x?
4. A function has f(0) = 1, f′(0) = 2, f″(0) = 6 and f‴(0) = 12. What is its third-degree Taylor polynomial about x = 0?
5. |f⁽⁴⁾(x)| ≤ 3 on [0, 1]. The third-degree Taylor polynomial about 0 is used to estimate f(1). What is the Lagrange error bound?
Need support with this topic?
In a free 45-minute intro call we assess your level and build a study plan tailored to you.
Free intro call